Answer:
B.
Step-by-step explanation:
It would seem that the third answer would be right but I am only 60% sure if you do not know the answer for sure, choose C but if you would rather get the 100% answer just wait
That’s the same equation but different format.
Hello,
Answer D -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12 U 12≤x<27 ⇔ -3<x<27
