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svlad2 [7]
3 years ago
6

Consider the Fourier sine series of each of the following functions. In this exercise do not compute the coefficients but use th

e general convergence theorems (Theorems 2, 3, and 4) to discuss the convergence of each of the series in the pointwise, uniform, and L2 senses.(a) f (x) = x3 on (0, l).(b) f (x) = lx − x2 on (0, l).(c) f (x) = x−2 on (0, l).
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

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Evaluate the following expression when x = -5 and y = 25.
kykrilka [37]

Answer:

<u>The correct answer is A. 3,120.</u>

Step-by-step explanation:

Let's solve the expression for x = -5 and y = 25, this way:

(5|x| - y³)/x

Replacing x and y, we have:

(5 * 5 - 25³)/-5 (Absolute value of -5 is 5 in the numerator but we keep it without changes in the denominator)

(25 - 15,625)/-5

-15,600/-5

3,120

<u>The correct answer is A. 3,120.</u>

3 0
3 years ago
What is the domain of the relation shown<br> on the graph?
rosijanka [135]

Answer:

where is the graph?........

7 0
2 years ago
What two numbers can multiply to get -84 but can add up to get -17?
miss Akunina [59]

Answer:

<em>-21 and 4</em>

Step-by-step explanation:

They multiply to a negative number, so you need a positive number and a negative number.


5 0
3 years ago
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I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
3 years ago
10+2b-4+5b <br> = ( )b+( ) help please!!!
bagirrra123 [75]

The solution is (7)b+(6)

Hope it helps!

3 0
3 years ago
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