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siniylev [52]
4 years ago
5

What is the circumference of the circle in terms of pi? The radius is 2.2 and I got 13.82 but the choices are 1.1, 1.21, 2.2 and

4.4 im so confused so could someone please explain what i did wrong?
Mathematics
2 answers:
nevsk [136]4 years ago
8 0
<span>The question pretty much explains it. Remember that pi is the ratio of the circumference to diameter and has the approximate value of 3.14159.... And you've been given a radius of 2.2. Since the diameter is twice the radius, that means that the diameter is 2.2*2 = 4.4, so the total circumference is 4.4 times pi. The value of 13.82 is the actual circumference, but remember the question "... in terms of pi" So the answer is 4.4</span>
NemiM [27]4 years ago
6 0
C = 2 <span>π r
C = 2 </span>π <span>(2.2)
C = 4.4 </span><span>π (in term of pi)

answer
4.4</span><span>π </span>
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Answer:

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Step-by-step explanation:

Given:

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3 years ago
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What is the ratio of the perimeter of ΔHKO to the perimeter of ΔFGO
Lera25 [3.4K]

Answer:

Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is \frac{1}{2}

Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is \frac{1}{4}

Step-by-step explanation:

Part 1)

we know that

If two figures are similar , then the ratio of its perimeters is equal to the scale factor

In this problem

Triangles HKO and FGO are similar by AAA Theorem

Find the scale factor

The scale factor is equal to the ratio of its corresponding sides

\frac{4}{8}=\frac{7}{14}=\frac{1}{2}

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO

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Area of ΔGFO

A=8*14/2=56\ units^{2}

The ratio of its areas is equal to

\frac{14}{56}=\frac{1}{4}

Alternative Method

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem we have that

The scale factor is \frac{1}{2}

so

squared the scale factor

(\frac{1}{2})^{2}=\frac{1}{4} ----> is correct

7 0
3 years ago
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7 0
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PLEASE Help!! What is the solution of the equation? Eliminate any extraneous solutions.
BabaBlast [244]
D. -4

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sq rt of 3x+28 = x+8
square both sides of the equation

3x + 28 = x^2 + 16x + 64

subtract x^2+16x+64 from both sides
group common terms
-13x-36-x^2=0

rearrange and put in quadratic form

x= -13 +/- sq rt of 13^2-4(1)(36) over 2(1)

subtract 169 by 144

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x = -13+5 over 2
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now plug in x

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sq rt of 3(-9)+28    -8= -9

-4 = -4
but
-7 does not = -9

so -4 is the solution
3 0
4 years ago
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