Answer:
Thickens (Height) = 0.068 cm
Step-by-step explanation:
Given:
Diameter of disc = 14 cm
Radius of disc = 14 / 2 = 7 cm
Surface area = 3 cm²
Find:
Thickens (Height)
Computation:
Disc is a cylinder in shape
Surface area = 2πrh
3 = 2(22/7)(h)(7)
3 = 44(h)
Thickens (Height) = 0.068 cm
Answer:
Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is 
Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is 
Step-by-step explanation:
Part 1)
we know that
If two figures are similar , then the ratio of its perimeters is equal to the scale factor
In this problem
Triangles HKO and FGO are similar by AAA Theorem
Find the scale factor
The scale factor is equal to the ratio of its corresponding sides

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO
Area of ΔKHO

Area of ΔGFO

The ratio of its areas is equal to

Alternative Method
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
In this problem we have that
The scale factor is 
so
squared the scale factor
----> is correct
ignore what's above it, using the distance formula with the two points you get approximately 6.71
D. -4
sq rt of 3x+28-8=x
add 8 to both sides
sq rt of 3x+28 = x+8
square both sides of the equation
3x + 28 = x^2 + 16x + 64
subtract x^2+16x+64 from both sides
group common terms
-13x-36-x^2=0
rearrange and put in quadratic form
x= -13 +/- sq rt of 13^2-4(1)(36) over 2(1)
subtract 169 by 144
x= -12 +/- sq rt of 25 over 2
solve for both sides
x = -13+5 over 2
=-4
x= -13-5 over 2
= -9
now plug in x
sq rt of 3(-4)+28 -8=-4
sq rt of 3(-9)+28 -8= -9
-4 = -4
but
-7 does not = -9
so -4 is the solution