Answer:
Step-by-step explanation:
F(x) = 2^x
64 = 2^x
2^6 = 2^x
x = 6
f(x) = 2^x
log (f(x)) = x log 2
x = log (f(x)) / log 2 = log_2 (f(x))
Therefore, the required logarithmic function is x = log_2 (f(x))
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Answer:
−3y2−8y−12
Step-by-step explanation:
Let's simplify step-by-step.
−5y2−9y−4−(−2y2−y+8)
Distribute the Negative Sign:
=−5y2−9y−4+−1(−2y2−y+8)
=−5y2+−9y+−4+−1(−2y2)+−1(−y)+(−1)(8)
=−5y2+−9y+−4+2y2+y+−8
Combine Like Terms:
=−5y2+−9y+−4+2y2+y+−8
=(−5y2+2y2)+(−9y+y)+(−4+−8)
=−3y2+−8y+−12
1.7n +1
I think the is the answer
I hope this helps :)
-2x=-4 or x=2
2x =-4 or x=-2
