Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
Step-by-step explanation:
y = y
x - 2 = 2x - 3 - 3x²
3x² + x - 2x = - 3 + 2
3x² - x = - 1
.
a = 3, b = -1, c = 0
.
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Substitution :
y = x - 2
y = ⅓ - 2
y = ⅓ - 6/3
y = - 5/3
y = - 1 ⅔
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Answer:
parameter
Step-by-step explanation:
True. If the angle is straight it must be 180 degrees, then it's just a line
