Given :
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.
To Find :
How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.
Solution :
Mass of copper in 50 gm alloy = 
.
Mass of copper in 78 gm alloy = 
.
Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.
Percentage of copper in resulting mixture :
Hence, this is the required solution.
Answer:
0.0558
Step-by-step explanation:
It
can be described useing two other undefined terms :- point & line
Answer:
D would be the answer Nonth grades at peak school
Answer:
The best way of writing this answer in an inequality pattern is 50 ≤ x ≥ 70
Step-by-step explanation:
The variable "x" is said to be greater than or equal to 50, that means that x could be 50, 51, 52, 53, 54......to infinity, all these values are true for x.
The second solution said x is greater or equal to 70. This also means that x could be 70, 71, 72, 73, ......... to infinity.
The inference that can be drawn from here is that x actually started from 50, so anything lesser than 50 is lesser than x, so 50 ≤ x. We can join the two answers together to get a range in a form like: 50 ≤ x ≥ 70
