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vladimir2022 [97]
3 years ago
15

What multiplication expression is equal to 3/4 divided by 1/3

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

<u>3</u> * <u>3</u>

4    1

Step-by-step explanation:

To convert division problems with fraction into multiplication problems use the KCF rule

  • Keep the 1st Fraction the same
  • Change the division sign to a multiplication sign
  • Flip the fraction (reciprocal)

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Convert 6 kilometers to yards
NISA [10]
1 km=1093.61yards

6 km= 6*1093.61yards
6 km= 6561.66yards

Answer= 6561.66 yards
7 0
3 years ago
Consider the matrices.<br> What products are defined for these matrices?
pychu [463]

Answer:

Shows how to quickly check if a matrix product is defined and, if it is, how to ... You can use this fact to check quickly whether a given multiplication is defined.

Step-by-step explanation:

6 0
3 years ago
What is the area, in square inches, of the isosceles trapezoid below?
zimovet [89]

Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

      Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

6 0
3 years ago
Help fast and thankssss god bless
Wewaii [24]

Answer:

1.

336-6=330

330÷6=55

55 Students in each bus

2.

242-11=231

231÷7=33

Each book was 33 dollars

3.

5+30+100=135

The smallest number is 5

4.

18-3=15

15÷8=1.8

Each candy bar was 1.8 dollars

5.

14-9=5

Her allowance is 5 dollars

6.

4+20+60=84

The smallest number is 4

7.

12-7=5

5×2=10

She had 10 in the begining

4 0
3 years ago
Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
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