Question

After pulling his car off to the side of the road during a rainstorm, travis isdismayed to find that the car has become stuck in the mud. travis ties oneend of a rope to the front of the car and the other end to a tree 12.00 m awayas shown.
a.if travis can exert a force of 610 n on the rope, moving it 1.00 min the direction shown, how much force will the rope exert on the car?


b.whyis this method better than simply tying a rope to the front of the car andpulling the car straight out?

Answer 1

Part a)

here as per the situation shown we can say that the tension force at the position of applied force is given as

$F = 2Tsin\theta$

here

$\theta$ = angle of rope with horizontal

$tan\theta = \frac{1}{6}$

so we will have

$\theta = 9.46 degree$

now we can say

$F = 610 N$

$610 = 2Tsin9.46$

$T = 1855.2 N$

so the tension force in the string is 1855.2 N

Part B)

this method is better then pulling the car directly because if we pull the car directly then the force on the car is 610 N while in this case we get almost 3 times more force so it is better way to pull the car