All categories

3 years ago

!!HELP HELP!!

Physics

1 answer:

borishaifa [10]3 years ago

6 0

Answer:

7.5s

Explanation:

Given parameters:

Velocity = 30m/s

Deceleration = 4m/s²

Unknown:

Time it takes for the car to come to complete rest = ?

Solution:

To solve this problem, we use the kinematics expression below:

v = u + at

Since this is a deceleration

v = u - at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

v - u = -at

0 - 30 = -4 x t

-30 = -4t

t = 7.5s

You might be interested in

With a 12 V battery, what is the voltage drop across each resistor?

anzhelika [568]

Call me delusional, but I can't shake the weird hunch that there's supposed to be
a drawing to go along with this question, showing the values of the resistors and
exactly how they're connected to the battery.

In a series circuit, the voltage divides across the resistors in proportion to
their resistances. If two resistors in series are the only things connected to
your battery, then the voltage across each resistor is . . .

(12 volts) x (the resistance of that one resistor) / (the sum of both resistors) .

8 0

3 years ago

If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is

navik [9.2K]

Answer:

15 and Increasing

Explanation:

Hope this helps

Have a wonderful day and many more to come

Alexis~

~A.K.A Moon~

7 0

2 years ago

Two very small charged particles exert an electrostatic force F on each other. If the distance between them is doubled, the forc

Solnce55 [7]

Answer:

The answer is D

Explanation:

Your welcome

4 0

3 years ago

What creates more pressure?

Evgesh-ka [11]

It is C, gasses with less kinetic energy, i did this and i think i remember it was C

8 0

3 years ago

Equipotential surfaces a) make an angle of 45 degrees with the electric field. b) are parallel to the electric field. c) are per

Schach [20]

Answer:

Option c) are perpendicular to the electric field

Explanation:

Equipotential surfaces are perpendicular to the electric field. the electric field lines are projected outwards from the equipotential surface, i.e., the lines of the electric field are at 90 $^{\circ}$ to the equipotential surface.

Equipotential surface are those surfaces that have the same potential at any point on the surface. Thus the potential difference at any point on the surface is zero due to same potential.

Any charge particle on this surface will move in a perpendicular direction to the Coulombian force. No work is done by the force on a particle moving on an equipotential surface.

7 0

3 years ago