All categories

2 years ago

Find f(x) - g(x) *

Mathematics

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:

3x^3+13x^2-3x+7

Step-by-step explanation:

I dont know if your question is complete.

f(x) - g(x)

$(4x^3+6x^2-3x+9)-(x^3-7x^2+2)\\4x^3+6x^2-3x+9-x^3+7x^2-2\\3x^3+13x^2-3x+7$

You might be interested in

Idahtonye has ₦50.00. He buys six mangoes and gets ₦2 change. Find the average cost of one mango. step by step explanation.

arsen [322]

Answer:

The average cost of one mango = c = ₦8

Step-by-step explanation:

Let 'c' be the average cost of one mango

The original amount Idahtonye has = ₦50.00

The amount of mangoes Idahtonye buys = 6 mangoes

As he gets back the change of ₦2 after paying ₦50.00 to buy 5 mangoes.

Thus the equation becomes

50 - 2 = 6c

48 = 6c

dividing both sides by 6

48/6 = 6c/6

c = 8 ₦

Therefore, the average cost of one mango = c = ₦8

8 0

3 years ago

Write a linear function f with the given values f(-3)=5, f(-1)=5

tiny-mole [99]

Answer f

Step-by-step explanation:

4 0

3 years ago

Which triangle is NLM congruent to? Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

8_murik_8 [283]

Answer:

XYZ

Step-by-step explanation:

due to the angles being equivalent to eachother(NL angles being equal to XZ). The M and Y are equal to eachother.

3 0

3 years ago

There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

3 years ago

How many numbers are 10 units from 0 on the number line?

agasfer [191]

It would be 10 to the right when you add from 0

5 0

3 years ago

Read 2 more answers