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Troyanec [42]
3 years ago
8

If ΔABZ≅ΔDEC, which of the following statements is not true?

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer

A. ZE=CE

Step-by-step

nydimaria [60]3 years ago
5 0

Answer:

  A. ZE≅CE

  C. CD≅BA

Step-by-step explanation:

The first choice is absurd, because point E is not part of both triangles. It is obviously NOT TRUE.

However, we also find that choice C is NOT TRUE. Compare it to choice B, which is true.

Since no sides of the triangles are marked as congruent, choices B and C cannot both be right. Choice B involves corresponding segments; choice C does not.

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How does a set of integers differs from the set of whole numbers ? Please help
MariettaO [177]
The difference between set of whole numbers and a set of integers is that:

Whole numbers = {0, 1, 2, 3, 4, 5...}
Integers = {..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...}

If we name contents of the first set as n, in the second set you can have 2n-1 numbers (because we count 0 only once in both sets).
7 0
3 years ago
What is 5 + 2^3 divided by 4 - 2
V125BC [204]

Answer:

6

Step-by-step explanation:

5+2^{3}/4-2

2^{3} = 2 x 2 x 2 (12)

5+ 12 / 4-2

5 + 3 - 2

6

5 0
3 years ago
Read 2 more answers
Jerry has a part-time job at a supermarket. The ordered pairs show the number of hours he worked for (input values) and the numb
Karo-lina-s [1.5K]

Answer:

Yes

Step-by-step explanation:

The ordered pairs are (6,72) (8,96) (5.5, 66) (9,108) (7,84).

The number of hours worked is x and the money earned is  y.

Let us divide the values of y by x

\dfrac{72}{6}=12

\dfrac{96}{8}=12

\dfrac{66}{5.5}=12

\dfrac{108}{9}=12

\dfrac{84}{7}=12

The fuction which defines the above ordered pairs is y=12x

It can be seen that the amount of money earned is 12 times the number of hours worked.

So, per hour Jerry earns 12 dollars.

Hence, the ordered pairs are relation.

8 0
3 years ago
During a bike challenge riders have to collect various colored ribbons each half mile they collect a red ribbon each “eighth of
Ahat [919]

Step-by-step explanation:

ijsjnsns

jjwjwjwjhehwhwjwjwnwjwjwhhwhw

3 0
3 years ago
Please I need this quick!!! 15 points
professor190 [17]
Let the number be n.

Then:

n^2 + (1/n)^2 = 82/9; find n.  Find the LCD; it is 9n^2.

Mult all 3 terms by 9n^2:
                                                                  82*9n^2
9n^4 + 9 = (82/9)(9n^2)  =>    9n^4 + 9 = ------------  
                                                                        9
Then 9n^4 - 82n^2 + 9 = 0

I used my graphing calculator to find that n = 3.  

Let's check:     is 3^2 + (1/3)^2 = 82/9?
                        Is   9   + 1/9 = 82/9?
                        Is  81 + 1 = 82?   YES.  So, n=3 is a solution.

7 0
3 years ago
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