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kap26 [50]
2 years ago
12

Solve for X when......................

Mathematics
1 answer:
weeeeeb [17]2 years ago
5 0

Answer:

-2 2

3 0

-1 -5

Step-by-step explanation:

-2 + 0 = -2 -5 + 7 = 2

1 + 2 = 3 0 + 0 = 0

3 + (-4) = -1 - 4 + (-1) = -5

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The diagonal of rectangle ABCD measures 2 inches in
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Answer:

B. √3

Step-by-step explanation:

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7 0
3 years ago
3y-6x=9 another equation that forms a system of equations that has infinitely many solutions?
Margaret [11]

you need another equation to solve them simultaneously since they are two unknown

8 0
3 years ago
Which vector best describes the translation below?
Nimfa-mama [501]
<h3>Answer: Choice A)  <9,0></h3>

Explanation:

Focus on one of the points in the figure on the left. Let's say we go for the upper left corner point (-7, 4)

Notice it moves to the corresponding image point (2,4). It has shifted 9 units to the right to follow the translation rule (x,y) \to (x+9, y). We've added 9 to the x coordinate, and the y coordinate stays the same.

This notation can be shortened to <9, 0>

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8 0
2 years ago
Which of the following are identities? Check all that apply
Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}

Double angle tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula sin2\alpha =2sin\alpha *cos\alpha

sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)

D) False No further development towards a Trig Identity

[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)

7 0
3 years ago
Read 2 more answers
Select all that have a value of 0.<br> -cos pi/2<br> -cos 0<br> -sin 0<br> -sin 3pi/2<br> -tan pi
Lapatulllka [165]
Sin 0 sin 3pi/2 and tan pi

cos pi/2 is -.5
cos 0 is 1
8 0
3 years ago
Read 2 more answers
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