Answer:
The answer is: 8a + 5b - 9
-3+3x=-2(x+1)
First: I will get rid of the bracket:
-3+3x=-2x-2
Now, all the x goes to the left side, all the numbers without x to the right side:
3x+2x=-2+3
we add up"
5x=1
divide by 5:
Answer:f(x)=x2 +1
Step-by-step explanation:
The one represents C in the standard form and it can also be used to represent graph placement so +1 can also represent the vertex going up 1 on the y
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
Answer:
Let s be the number of shorts and t be the number of T-shirts. s shorts cost $12s and t T-shirts cost $5t, then you have to find min and max value for the function f(s,t)=12s+5t.
The shaded domain (see image) is defined from the system of unequalities. The green lines are the graphs of function f(x,y) and it intersects domain in first point (0,5) (the minimum point) and in last point (20,0) (the maximum point). So,
.
Step-by-step explanation:
