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3 years ago

The height of a triangle is 9, the length is 5, what is the third side?

1 answer:

5 0

Use the Pythagorean Theorem to solve for the third side. The third side must be the hypotenuse since the height (vertical leg) is 9, and the length (horizontal leg) is 5.

a² + b² = c², where a and b are the legs and c is the hypotenuse. Plug in 5 and 9 for a and b; solve for c.

5² + 9² = c² ⇒ 25 + 81 = c²

106 = c²

Square root both sides.

c = 10.3

Third side: 10.3

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What was the simple interest rate on a $8,000 investment that was left in an account for 18 months and earned $360 in interest

diamong [38]

Answer:

0.375%

Step-by-step explanation:

i=P*R*T

$360=$8000*R/100*18/12

$360=$960R

$360/$960=$960/960

0.375%=R

7 0

2 years ago

Read 2 more answers

Ted earned $4,300 from his summer internship that he plans to invest so that he can buy a used car after three years. Ted choose

olganol [36]

Answer: Yes he will be

Step-by-step explanation:

To find out if Ted can afford the car, find the future value of $4,300 in three years.

First convert the number of years and rates to quarterly values as this is the compounding period:

Term = 3 * 4 quarters = 12 quarters

Rate = 5.5% / 4 = 1.375% per quarter

Future value = Amount * ( 1 + rate) ^ term

= 4,300 * ( 1 + 1.375%)¹²

= $5,065.69

<em>Considering that Ted makes $5,065.69 in 3 years, he will be able to buy a car that costs $4,700.</em>

8 0

2 years ago

Pls help me in this question

kari74 [83]

Answer:

Step-by-step explanation:

since the diagonal are equal in length

6x-8=2x+4

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4 0

2 years ago

Plz plz help me so i can get a good grade

Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

= 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = $\frac{1}{2}bh$

$$=\frac{1}{2}\times 31\times 20$

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = $\frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}$

$$=\frac{1}{2}\times {(16+31)}\times{15}$

$$=\frac{1}{2}\times {47}\times{15}$

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

= 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

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2 years ago

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Anastaziya [24]

Answer:

Step-by-step explanation:

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1 year ago