Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.
Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.
But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.
Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.
It's 3 yards wide and 9 yards long.
Step-by-step explanation:
2x + 10y = 50 ... 1
1.5x + 25y = 90 ...2
...1 × 2.5
5x + 25y = 125 ...3
...3 - ...2
3.5x = 35
x = 10
replaced x = 10 in ...1
2(10) + 10y = 50
20 + 10y = 50
10y = 50 - 20
10y = 30
y = 3
Answer:
Probability
Step-by-step explanation:
Probability is the likelihood of the occurrence of an event and are numbers.
Answer:
x=-5, y=-8. (-5, -8).
Step-by-step explanation:
-x+2y=-11
5x-8y=39
---------------
5(-x+2y)=5(-11)
5x-8y=39
---------------------
-5x+10y=-55
5x-8y=39
--------------------
2y=-16
y=-16/2
y=-8
-x+2(-8)=-11
-x-16=-11
-x=-11+16
-x=5
x=-5
Answer:
Step-by-step explanation:
Remark
The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.
If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)
So, let's go.
Givens
1/2 of ST = 1/2 32 = 16
12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.
Solution
KT^2 = 16^2 + 12^2
KT^2 = 256 + 144
KT^2 = 400
KT = sqrt(400)
KT = 20
RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.
