Step-by-step explanation:
the answer is in picture
(<em>A</em> ∩ <em>B</em>)' is the complement of <em>A</em> ∩ <em>B</em>, or the set of all elements in the universal set <em>U</em> that do not belong to <em>A</em> ∩ <em>B</em>.
<em>A</em> ∩ <em>B</em> is the intersection of <em>A</em> and <em>B</em>, or the set of all elements common to both <em>A</em> and <em>B</em>.
We have
<em>A</em> = {q, s, u, w, y}
<em>B</em> = {q, s, y, z}
so that
<em>A</em> ∩ <em>B</em> = {q, s, y}
Then
(<em>A</em> ∩ <em>B</em>)' = {r, t, u, v, w, x, z}
which makes (c) the answer.
Answer:
77
Step-by-step explanation:
85-69=16
16/2=8
69+8=77
Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
The answer to this question is "B)$126" The hourly pay is 21$