Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
Answer:
t = -1
Step-by-step explanation:
-4 = 2t - 2
2t = -2
t = -1
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I think 1.99?
I have no idea but I think it’s that
Answer:
Step-by-step explanation:
2x² - 8x - 24 = 0
2x² - 12x + 4x - 4*6 = 0
2x(x-6) + 4(x - 6) = 0
(x - 6)(2x + 4) = 0