Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
Answer:
27°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
let the third angle be x , then
x + 90° + 63° = 180°
x + 153° = 180° ( subtract 153° from both sides )
x = 27°
Answer:
7 and 11
Step-by-step explanation:
Let the two numbers be x and y
x+y = 18
x-y = 4
Add the two equations together to eliminate y
x+y = 18
x-y = 4
----------------
2x +0y = 22
Divide each side by 2
2x/2 = 22/2
x = 11
Solve for y
x+y = 18
11+y =18
Subtract 11 from each side
11+y-11 =18-11
y = 7
The two numbers are 7 and 11
1 because 11 can only go into 16 once
