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Goryan [66]
3 years ago
14

From the first quiz to the second quiz, a score dropped eight points. The score on the second quiz was 39. What was the first qu

iz score?
Mathematics
2 answers:
frutty [35]3 years ago
5 0

Answer:47

Step-by-step explanation:

Because 39+8=47.

ArbitrLikvidat [17]3 years ago
5 0

\text{We're trying to find the score of the 1st quiz}\\\\\\text{We know that their second score was 39}\\\\\text{We also know that they dropped 8 points in the 2nd quiz}\\\\\text{To find the score of the 1st quiz, add 8 and 39}\\\\39+8=47\\\\\boxed{\text{1st test score was a 47}}

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alex runs on the track at the school each weekday morning if he runs 5.9 miles each day about how much does he run every month
vovangra [49]
Since Alex runs on weekday mornings he most likely runs 118 miles a month.
3 0
3 years ago
I NEED HELP PLEASE HELP ME
CaHeK987 [17]

Answer:

6 donuts

Step-by-step explanation:

first divide the cost of the donuts by the amount of donuts per box

6 donuts:

2.10 ÷ 6 = .35 per donut

12 donuts

5.40 ÷ 12 = .45 per donut

18 donuts

7.20 ÷ 18 = .40 per donut

24 donuts

12 ÷ 24 = .50 per donut

3 0
3 years ago
Please give an explanation as well as an answer :)
STatiana [176]

Answer: It is 10 because there are 2 other faces and 8+2=10

Step-by-step explanation:

3 0
3 years ago
Options: <br> y= -2x - 6<br> y= 2/3x + 6<br> y= -2/3x + 6<br> y=2x + 6
melisa1 [442]

Answer:

y = - \frac{2}{3} x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (6, 2) ← 2 points on the line

m = \frac{2-6}{6-0} = \frac{-4}{6} = - \frac{2}{3}

The line crosses the y- axis at (0, 6) ⇒ c = 6

y = - \frac{2}{3} x + 6 ← equation of line

8 0
3 years ago
Does anyone know how to do this?
kolezko [41]

Answer:

  • x = 1
  • y = -7

Step-by-step explanation:

The coefficients of x and y do not have any "nice" relations, so doing this by elimination is just "brute force" with no particular subtlety.

After multiplying by appropriate numbers, you want the coefficient of one of the variables in one equation to be the opposite of the coefficient of the same variable in the other equation. Here, we can get that by multiplying the first equation by 7 and the second equation by 2.

  7(2x +3y = -19)   ⇒   14x +21y = -133

  2(-7x +2y = -21)   ⇒   -14x +4y = -42

Adding these equations with opposite x-coefficients eliminates the x-terms. (That is how the "elimination" method gets its name.)

  (14x +21y) +(-14x +4y) = (-133) +(-42)

  25y = -175 . . . . . . . . simplify

  y = -7 . . . . . . . . . . . divide by 25

Substituting this value into the first equation gives ...

  2x +3(-7) = -19

  2x = 2 . . . . . . . . . add 21

  x = 1 . . . . . . . . . divide by 2

The solution is x = 1, y = -7.

_____

<em>Additional comment</em>

The multipliers used in this process are essentially the coefficients of one of the variables, with one of them negated. Here, we chose the x-coefficients, because negating one of them gives two positive multipliers. We judge it easier to do the arithmetic using positive numbers.

Had we chosen to use the y-coefficients (3 and 2) for our multipliers, we would probably multiply the first equation by 2, and the second equation by -3. That way, the remaining x-coefficient would be positive.

Planning ahead is helpful, but not essential. It can help to avoid errors and make the work easier to do.

3 0
3 years ago
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