Answer:
Step-by-step explanation:
h = -6
+20t + 4
I will use calculus, maybe that's not how you're supposed to do this
-12t +20 =0
12t = 20
t = 20 /12
t = 1 
t = 1 
there will be a max at 1.6666666666 seconds
-6*
+ 20 * 1.6666666666 +4
= 16.666666666666 + 33.333333333333 + 4
= - 16 + 33 
+ 4
= 20 feet max height ( not too high, for a rocket)
time of flight:
0 = -6 +20t + 4
use quadratic formula to find t
-20 +- sqrt [ 
- 4*(-6)*4 ] / 2*(-6)
-20 +- sqrt [400 + 96 ] / -12
-20 +- sqrt [496 ] / -12
-20 +- 22.27105 / -12
try the negative option 1st
-42.27105 / -12
3.522 seconds. time of flight
when will the rocket be at 12' ? :
12 = -6 +20t + 4
0 = -6 +20t -8
use quadratic formula again to find t
-20 +- sqrt [ - 4*(-6)*(-8) ] / 2*(-6)
-20 +- sqrt [ 400 - 192 ] / -12
-20 +- sqrt [208 ] / -12
-20 - 14.4222 / -12
-34.4222 / -12
2.8685 seconds ( on the way down)
and
-20 + 14.4222 / -12
-5.578 / - 12
0.4648 seconds ( on the way up )
10x10x10x10=10^4
10x10x10x10=10,000
6x10^5=6x100000
6x10^5=600000
Answer:
Practice started at 1:55 pm.
Step-by-step explanation:
Whatever is adding with 0 its that number its like mulitipulcation with 1 because whatever is times by one like 25x1= 25
Answer:
Area of model pond = 45.6 inch² (Approx.)
Step-by-step explanation:
Given:
Circumference of circular pond = 24 inches
Find:
Area of model pond
Computation:
Circumference of circle = 2πr
Circumference of circular pond = 2πr
24 = 2[22/7][r]
Radius r = [24 x 7] / [2 x 22]
Radius r = 3.81 inch (Approx.)
Area of circle = πr²
Area of model pond = πr²
Area of model pond = (22/7)(3.81)²
Area of model pond = [3.1428][14.5161]
Area of model pond = 45.6 inch² (Approx.)
