The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Kilograms is probably the best answer.
Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).
Solve for d<em>y</em>/d<em>x</em> :
If <em>y</em> ≠ 0, we can write
At the point (1, 1), the derivative is
As given Chole and Tinos age , the present age of Tino is equal to 15 years.
As given,
Let x and y be the present age of Chole and Tino. respectively.
Combined age = 48
Given condition,
x + y = 48 _______(1)
Three years ago
x - 3 = 2y
⇒x =2y +3 _______(2)
Substitute the value of x in (1),
2y+3 +y =48
⇒ 3y = 45
⇒ y = 15years
Therefore , as given Chole and Tinos age , the present age of Tino is equal to 15 years.
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Answer:
0.5
Step-by-step explanation:
If you add 0.5 to -0.5, it will equal 0.
