Please note that since magnesium is in group 2 it has a valency of 2+ and so the formula for magnesium hydroxide is
M
g
(
O
H
)
2
[Mistake in question]
This is a typical neutralization reaction of an acid with a base to form a salt and water. The reaction is exothermic, gives off heat,
Δ
H
<
0
, and may be balanced by adding balancing numbers in front, ie adding molecules, in order to ensure that the total number of atoms of each element is the same on the left and right hand sides of the equation.
Doing so we obtain :
2
H
3
P
O
4
+
3
M
g
(
O
H
)
2
→
M
g
3
(
P
O
4
)
2
+
6
H
2
O
Ksp(the solubility product constant) = [Cu⁺] [I⁻]
So, the Ksp for Cui would be:
Ksp = (2.26 × 10⁻⁶) (2.26 × 10⁻⁶) = 5.11 x 10⁻¹²
<h3 />
Formula used:
K = ![K_{sp} = [A^+]^a [B^-]^b](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BA%5E%2B%5D%5Ea%20%5BB%5E-%5D%5Eb)
, where
Ksp = solubility product constant
A⁺ = cation in an aquious solution
B⁻ = anion in an aqueous solution
a, b = relative concentrations of a and b
<h3><u>
Definition</u></h3>
The equilibrium constant for a solid material dissolving in an aqueous solution is the SOLUBILITY PRODUCT CONSTANT, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.
Take into account the general dissolving response (in aqueous solutions) below:
aA(s)⇔cC(aq)+dD(aq)
The molarities or concentrations of the products (cC and dD) must be multiplied in order to find the Ksp. Any product that has a coefficient in front of it must be raised to the power of that coefficient (and also multiply the concentration by that coefficient).
Learn more about the concept of Ksp through the link:
brainly.com/question/1419865
#SPJ4
The correct answer to this question is this one:
find the energy of one photon:
<span>E=h*<span>c/λ
</span></span>
divide the energy given by the energy of one photon of that wavelength
What I've done so far is convert wave length to m and energy to j.
E photon = h * x / wave length
E = (6.626 x 10^-43)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^18 J
3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 16
E = (6.626 x 10^-34)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^19 J
3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ -16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is 1.81 × 10^24 photons
3.38 x 10 ^-19 J
should be negative
then 3.38 x 10 ^18 J x 1kJ/1000 J
you're converting from J to kJ.. just like meters to kilometres, you wouldn't multiply you would divide
I think it’s the last answer.
