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2 years ago

What is the lightest particle in the following 1)electron 2)proton 3)neutron 4)photon

Chemistry

2 answers:

goldfiish [28.3K]2 years ago

6 0

The answer would be electron

Anuta_ua [19.1K]2 years ago

5 0

Answer:

1) Electron

Explanation:

It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.

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Is cooking raw tomatoes a physical or a chemical change?<br>Explain why?

salantis [7]

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3 years ago

1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.

LenaWriter [7]

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

4 0

2 years ago

Which element's atomic radius increases the most in size when it becomes ionized? A. Sodium B. Chlorine C. Fluorine D. Lithium

Drupady [299]

I am thinking Chlorine

5 0

3 years ago

Question 14 A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices tha

Yuki888 [10]

We must to know:

Cm = molarity = niu / Vs, when the niu = no. of moles and Vs = Volume of solution

the no. niu = mass / molecular mass of substance

molecular mass of C8H8 = 12x8+8x1 = 104 g/mol

=> niu = 1,5 / 104 = 0,0144 moles C8H8

=> Cm = 0,0144/0,225 = 0,06 mol/L

Cmm = molality = niu (C8H8) / mass of solvent (kg)

=> p = mass / V => mass (solvent) = p x V

=> 225 x 1,02 = 229,5 g solvent = 0,2295 kg solvent

=> Cmm = 0,0144 / 0,229,5 = 0,063

8 0

2 years ago

Read 2 more answers

Which conversion factor is needed to solve the following problem?

USPshnik [31]

Molar Volume is required to solve this problem. As we know that "1 mole of any gas at standard temperature and pressure occupies 22.4 L of volume". SO using this concept, we can calculate the volume of ammonia formed by reacting 54.1 L of Hydrogen gas as follow,

3 0

3 years ago