(please show work) offering 24 points !
1 answer:
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Answer:
Step-by-step explanation:
<u><em>Part B:</em></u>
The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.
<u><em>Part C:</em></u>
Coordinates of the midpoint of line BC ( y = - 1 ) are
( ,
) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>
Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = = 4
<h3>Answer:</h3>
We know that , so substitute that into the equation.
With negative powers, instead of making the result negative, you divide one by it. Mathematically speaking, . This makes our equation:
Finally, simplify the exponent.