Plzzzzz answer this!!!!♥️♥️

Here are 8 and 2 over 3 pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 5

FinnZ [79.3K]

Answer:

Probally 3

Step-by-step explanation:

6 0

4 years ago

PLEASE HELP!!!!!!!!!!!!CORRECT ANSWER WILL GET BRAINLIST

nadezda [96]

Answer: 2.4 degrees F

Step-by-step explanation:

4 0

3 years ago

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Suppose that the weight of seedless watermelons is normally distributed with mean 6.2 kg. and standard deviation 1.5 kg. Let X b

Oksi-84 [34.3K]

Answer:

A.

X ~ N(6.2kg, 2.25kg²)

B. What is the median seedless watermelon weight?____ kg.

6.2 kg

C. What is the Z-score for a seedless watermelon weighing 8 kg?

1.2

D. What is the probability that a randomly selected watermelon will weigh more than 7 kg?

0.2981

E. What is the probability that a randomly selected seedless watermelon will weigh between 4 and 5 kg?

0.1411

F. The 80th percentile for the weight of seedless watermelons is _____ kg.

7.5 kg

Explanation:

A. X ~ N(___ , ____ )

The distribution of a random variable in a sample extracted from a population that follows a normal distribution is represented by the notation:

X ~ N(μ, σ²)

Where:

X is the random variable
N stands for normal distribution function
μ is the median of the population
σ² is the variance of the population

Here, you have:

μ = 6.2 kg

σ² = (1.5kg)² = 2.25 kg²

X ~ N(6.2kg, 2.25kg²)

B. What is the median seedless watermelon weight?____ kg.

The median of a random variable that follows a normal distribution is equal to the mean, thus it is 6.2 kg.

C. What is the Z-score for a seedless watermelon weighing 8 kg?

The z-score is the standardized value of the random variable. It measures how far away is the variable from the mean.

It is calcuated with the formula:

$Z-score(X=x)=\dfrac{x-\mu}{\sigma}$

Thus for X=8:

$Z(X=8)=\dfrac{8-6.2}{1.5}=1.2$

D. What is the probability that a randomly selected watermelon will weigh more than 7 kg?

You want P(X>7)

You must use the tables for the standardized normal distribution.

Find the corresponding Z-score for X = 7

$Z(X=7)=\dfrac{7-6.2}{1.5}\approx0.53$

You must use a table for the standardized normal distribution which gives the cumulative distribution or area under the curve of the standard normal distribution and find P(Z>0.53).

That is the area to the right of Z=0.53. The table shows 0.2981.

Thus, the probability that a randomly selected seedless watermelon will weigh more than 7 kg is 0.2981

E. What is the probability that a randomly selected seedless watermelon will weigh between 4 and 5 kg?

For this case you must find the Z-scores for X=4 and X=5 and then find the area under the curve of the standardized normal distribution between those two Z-scores.

Z(X=4) = (4 - 6.2)/1.5 ≈ -1.47

Z(X=5) = (5 - 6.2)/1.5 = -0.8

In the table the area to the right of Z = - 1.47 is 1 - 0.0708 = 0.9292

And the area to the right of Z = - 0.8 is 1 - 0.2119 = 0.7881

Thus, the area in between is the difference 0.9292 - 0.7881 = 0.1411.

F. The 80th percentile for the weight of seedless watermelons is _____ kg.

The 80th percentile is the weigh of the top 20% seedless watermelons: this is 80% of the weighs are below that weight.

You must find the Z-score for which the area under the curve is less than 0.80.

The area less than 0.80 is 1 less the area that is less than 0.20.

From the table, the Zscore that defines the area less than 0.20 is 0.845 (interpolating).

Thus, the 80th percentile is the X value that makes the Z-score greater than or equal to 0.845:

Z ≥ 0.845

(X - 6.2)/1.5 ≥ 0.845

X ≥ 0.845 × 1.5 + 6.2

X ≥ 7.4675

X ≥ 7.5 kg ← answer

7 0

3 years ago

An employee was randomly chosen from a company's

masya89 [10]

Can you post more info

7 0

4 years ago

What are the values of x and y?

guajiro [1.7K]

The correct answer is:

x=64/15, y=136/15.

Explanation:

We will use the Pythagorean theorem to solve this.

For the smaller triangle, the legs of the triangle are x and 8, and the hypotenuse is 8. In the Pythagorean theorem, this gives us:
x²+8²=y²

Simplifying, we have:
x²+64=y².

For the large triangle, the legs of the triangle are y and 17, and the hypotenuse is 15+x. In the Pythagorean theorem, this gives us:
y²+17²=(15+x)².

Simplifying the left hand side we have:
y²+289 = (15+x)².

In order to simplify the right hand side, we write (15+x)² as the product of two binomials:
y²+289=(15+x)(15+x).

Multiplying the right hand side, we have:
y²+289=15*15+15*x+x*15+x*x
y²+289=225+15x+15x+x²
y²+289=225+30x+x².

We can now substitute the value from the smaller triangle in place of y²:
x²+64+289=225+30x+x².

Combining like terms, we have:
x²+353=225+30x+x².

Subtracting x² from both sides, we have:
x²+353-x²=225+30x+x²-x²
353=225+30x.

Subtract 225 from both sides:
353-225=225+30x-225
128=30x.

Divide both sides by 30:
128/30=30x/30
128/30 = x.

Both the numerator and denominator of this fraction are divisible by 2:
(128/2)/(30/2)=64/15=x.

Now we use this to find y; in our Pythagorean theorem equation from earlier, we have:
x²+64=y².

Using our value for x, we have:
(64/15)²+64=y².

Squaring the fraction, we have:
4096/225+64=y².

In order to write 64 as a fraction using 225 as the denominator, we multiply:
(64*225)/225=14400/225.

This gives us:
4096/225+14400/225=y²

Combining like terms,
18496/225=y².

Taking the square root of both sides, we have:
 $\sqrt{\frac{18496}{225}}=\frac{\sqrt{18496}}{\sqrt{225}}=\frac{136}{15}=y$

8 0

3 years ago

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