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KATRIN_1 [288]
3 years ago
9

Ms. Block's students are studying chemical reactions. A classic reaction occurs when a metal is added to hydrochloric acid. Migu

el and Kai added 30g of hydrochloric acid (HCl) to 30g of magnesium (Mg) in a large test tube; bubbles appeared, the test tube felt warm, and they could no longer see the magnesium. They found that the mass of the products of the reaction was 52g. Since the Law of Conservation of Matter stated that matter cannot be created or destroyed, they were puzzled about the difference in mass. What is the best explanation for the missing 8g? A) 8g of hydrogen gas escaped from the test tube. B) 8g of magnesium disappeared during the reaction. C) Miguel and Kai were not very proficient at using the beam balance. D) 8g of the mass produced the heat the boys felt at the end of the experiment.
Chemistry
2 answers:
azamat3 years ago
8 0
Since hydrogen gas is created when you mix magnesium /‘d hydrochloric acid, the best answers would be A/C but i would go for A
g100num [7]3 years ago
5 0

Answer:

the boys should cover the end of the test tube to a ballon

Explanation:

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Vsevolod [243]

Air masses form fronts when B, they collide with each other

7 0
4 years ago
What mass of ch4 is consumed when 587. 9 kj of energy is evolved from the combustion of a mixture of ch4(g) and o2(g)? show the
Juliette [100K]

The mass of CH₄ that is consumed is 10.598 g.

<h3>What is enthalpy?</h3>

The enthalpy of a system is defined as the sum of the internal energy of a system and the energy that is produced due to its pressure and volume.

It is given by

H = U+PV

The following reaction takes place during the combustion of CH₄

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

Energy evolved during the combustion, E = 587.9 kJ

Enthalpy of combustion of methane, ∆H = 890.3 kJ

No of moles of CH_4 =\frac{energy evolved}{enthalpy of combustion}

= 587.9 /890

Mass of CH₄  that is consumed = no of moles × molar mass of CH₄

  = 587.9 /890 × 16

   = 10.598 g

The mass of CH₄  which is consumed is 10.598 g

Learn more about enthalpy:

brainly.com/question/14047927

#SPJ4

6 0
1 year ago
Based on the number of valence electrons indicated by its location in the periodic table, which element's behavior would you pre
katrin [286]

Answer:

D

Explanation:

Elements in the same group (vertical columns) have the same number of valence electrons. These elements behave similarly because they will either give up or take the same number of electrons to fill their valence shell. Since potassium has 1 valence electron, it will most likely give up one electron. Out of all of the answer options, the only element that is in the same group as potassium is francium.

8 0
4 years ago
A liquid has a density of 0.87g/ml. What volume is occupied by 25g of liquid
irga5000 [103]

Answer:

29 mL

Explanation:

<h3>Equation</h3>

The question needs us to find the volume of the liquid. The equation for volume using density and mass is:

Volume = Mass / Density

<h3>Solve</h3>

We can substitute the given values for density and mass into the equation:

V=\frac{25\ g}{0.87\ g/ml}

V\approx29\ mL

<h3>Additional Comments</h3>

The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.

Below are the significant figure rules:

Nonzero digits will always be significant (eg. 54 --> 2 significant figures)

Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)

Zeroes between two nonzero digits will always be significant (eg. 504 --> 3 significant figures)

Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)

5 0
2 years ago
Why must sample spots be above the solvent in paper chromatography
marishachu [46]
Because if they are submerged in the solvent, they would dissolve! This would prevent them from seperating and not allow you to actually record anything
6 0
3 years ago
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