Question

011 10.0 points

Answer 1

Answer:

$-58.3^{\circ}C$

Explanation:

The frequency and the wavelength of a wave are related by the equation

$v=f\lambda$

where

v is the speed

f is the frequency

$\lambda$ is the wavelength

For the sound wave in this problem, we have

f = 634 Hz (frequency)

$\lambda=0.47 m$ (wavelength)

Therefore, the speed of the wave is

$v=(634)(0.47)=298 m/s$

The speed of sound in air depends on the temperature according to the equation

$v=333+0.6 T$

where T is the temperature.

In this problem, we know the speed, so we can calculate the temperature:

$T=\frac{v-333}{0.6}=\frac{298-333}{0.6}=-58.3^{\circ}C$