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vichka [17]
3 years ago
12

1. look at the sequence of pictures what happened to the Apple overtime. 2. no chemical was added to the Apple explain why the A

pple changed. 3. how could you test your answer to question 3. 4. what would affect increasing the amount of air surrounding the Apple have on the apple explain your answer. 5. how would slicing the apple into more pieces affect the Apple explain your answer. 6.the Apple in the picture is raw.A cooked Apple would not change the same way. Give a possible reason why.​

Chemistry
1 answer:
Goshia [24]3 years ago
8 0

Answer: it started too rot over time mold over time and decay and if you cooked a apple it would melt like ice cream cause of the heat waves and if the apple is surrounded by air i think what would happen it would still rot I guess but i wouldnt know for sure cause things with air take time too rot and things with air rot faster and slicing the apple into more pieces would make it decay or rot or mold faster cause its open and accepting everything it sees like bacteria bugs all that

Explanation: like the longer a apple is left half open it starts too rot then mold over time getting all bad and not good too eat or decay

read it all the stuff is in there i think

You might be interested in
If you begin with 4.0 grams of hydrogen and all of the oxygen that you need, how many grams of water can you make?​
yawa3891 [41]

    the water is 36 grams.

hope this helped

7 0
3 years ago
Consider the market for paper. Let market demand be given by inverse demand function P d (Q) = 60 − Q, where Q is tons of paper
MakcuM [25]

Answer:

See explaination

Explanation:

Demand for paper is given below:

P(Q)=60-Q,

Number of paper mills=20

The cost curve for firm is given below:

C(Q)=10Q2

The external cost in terms of pollution down river by production of paper is given below:

EC(Q)=10Q2

a. The optimal level of paper production by market can be calcuated by equating MC=P

20Q=P

Q=P/20

b. The optimal level of paper production by market can be calcuated by equating MC=P.

MC=20Q

60-(20Q)=20Q

Q=60/40

Q=1.5

Total quanity by 20 firms will be 1.5*20=30

c. The socially efficient level of paper output is calcuated below:

MC+EC'=20Q+20Q

60-(20Q)=40Q

Q=60/60

Q=1

Total quanity by 20 firms will be 1*20=20

The price will be P=60-20=40

d, The deadweight loss occurs as market price increases and quantity decreases due to the external cost . The deadweight loss is calcuated below:

DWL=(1/2)*change in price* change in quantity

=(1/2)*10*10=50

e. 20 firms merged into one firm to make monopoly firm. The cost function for the monopoly is given below:

Cm(Q)=20*10(Q/20)2

The marginal cost for the monopoly firm will be

MCm=Q

The marginal revenue for the firm is 60-2Q

For optimal output MR is equated to MC

60-2Q=Q

Q=20

P=40.

The monopoly outcome is below the perfect competition outcome and price is higher in comparison to perfect competition. The monopoly outcome is same as socially efficient outcome.

The total surplus for this outcome is sum of consumer surplus and producer surplus and subtraction of external cost

TS=CS+PS-EC

=(1/2)*20*20+(1/2)*40*20-10(20)2

=600-4000=-3400

Due to the external effects the total surplus to the society is negative. In perfect competition this effect is not considered and output produced is high therefore, the external cost will be higher with higher output leading to higher negative social surplus. Generally the monopoly outcome reduces the total social surplus but in case of externality, the monopoly total surplus is higher than the perfect competition.

3 0
3 years ago
A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio
myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

W = -P*(V_{2} - V_{1})

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K);  R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

V_{1} is the initial volume = 0.350 L

V_{2} is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*(V_{2} - 0.350) L

V_{2} = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

7 0
3 years ago
29.5 g of mercury is heated from 32°C to 161°C, and absorbs 499.2 joules of heat in the process. Calculate the specific heat cap
Finger [1]

Answer:

c = 0.13 j/ g.°C

Explanation:

Given data:

Mass of mercury = 29.5 g

Initial temperature = 32°C

Final temperature = 161°C

Heat absorbed = 499.2 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 161°C - 32°C

ΔT  = 129 °C

Q = m.c. ΔT

c = Q / m. ΔT

c = 499.2 j / 29.5 g. 129 °C

c =  499.2 j / 3805.5 g. °C

c = 0.13 j/ g.°C

5 0
3 years ago
11. If four gases in a cylinder each exert 6 atm, what is the total pressure exerted by the
Debora [2.8K]

Answer:

24 atm is the total pressure exerted by the gases

Explanation:

We propose this situation:

In a vessel, we have 4 gases (for example, hydrogen, Xe, methane and chlorine)

Each of the gases has the same pressure:

6 atm → hydrogen

6 atm → xenon

6 atm → methane

6 atm → chlorine

To determine the total pressure, we sum all of them:

Partial pressure H₂ + Partial pressure Xe + Partial pressure CH₄ + Partial pressure Cl₂ = Total P

6 atm + 6 atm + 6 atm + 6 atm = 24atm

8 0
3 years ago
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