MnO2 + 4HCl = MnCl2 + Cl2 + 2H2O
m(HCl) = 36.45/48.2 = 0.76
every 4 moles of HCl will only react with 1 mole MnO2 and there is less HCl therefore HCl will be used up first.
Excess MnO2 = 0.86 - (0.76/4) = 0.67m
grams MnO2 = 0.67x 86.93= 58.24grams left over.
Every 4 moles HCl will only form 1 mole Cl2 so m(Cl2)=0.76/4=0.19
0.19x70.9=13.47grams Chlorine formed
i'm not sure, so sorryyy!
Answer: The heat of combustion per gram of the material is 53.5 kJ
Explanation:
Let the heat released during reaction be q.
= Heat gained by calorimeter
Heat capacity of bomb calorimeter ,C = 38.29 kJ/°C
Change in temperature = ΔT = (27.04-23.61) °C = 3.43 °C
Total heat released during reaction is equal to total heat gained by bomb calorimeter.
Thus 2.455 g of material releases 131.3 kJ of heat
1 g of material releases =
of heat
Thus the heat of combustion per gram of the material is 53.5 kJ
In chemistry, yes...yes it is.