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natita [175]
3 years ago
7

Help please.

Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

4. Slope of function B = -slope of function A

Step-by-step explanation:

Given:

Function A is given as:

F(x)=-2x+1

The above equation is of the form y=mx+b, where m represents slope of the line.

Therefore, on comparing the function A with the above standard form, er conclude that, slope of function A is -2.

Now, from the graph of function, we consider any two points on the graph and determine the slope of the line using the two points.

Let us consider the points (x_1,y_1)=(1.5,0)\ and\ (x_2,y_2)=(3,3)

Now, the slope of the line passing through these two points is given as:

m_B=\frac{y_2-y_1}{x_2-x_1}=\frac{3-0}{3-1.5}=\frac{3}{1.5}=2

Therefore, slope of function B is 2.

Therefore, the correct relation between the slopes of the two functions is that the slope of function B is negative of the slope of function A.

m_B=-(m_A)=-(-2)=2

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5 0
1 year ago
To evaluate log2(3), Autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefor
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Answer:

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

Step-by-step explanation:

Given:

log₂(2) = 1

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To evaluate :  log₂(3)

Now,

we know that

logₓ(y) = \frac{\log(y)}{\log(x)}        (Here the log has same base in the numerator and the denominator i.e 10)

therefore,

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also,

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log(3) = 0.4771

thus,

log₂(3) =  \frac{0.4771}{0.3010}

or

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

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