Please help me I don't know

Mathematics

2 answers:

atroni [7]3 years ago

5 0

I would say it would be A because there is but idk lol im not really that good but i think it is :)

babymother [125]3 years ago

3 0

Yeah ts a because can see that the 5th graders have a not higher or longer bar

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the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o

natka813 [3]

Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant. This is, the equation has the form:

y = a(x + 4)(x - 2)

Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:

10 = a (6 + 4) (6 - 2)

Therefore, any of these equivalent equations can be solved to determine the value of a:

10 = a 6 + 40) (6 -2)

10 = a (10)(4)

10 = 40a

7 0

3 years ago

Read 2 more answers

Write (9,-4) and (1,6) in slope intercept form,

vesna_86 [32]

Answer:

y = -5/4x + 7 1/4

Step-by-step explanation:

The difference in y (10) over the difference in x (8)

7 0

1 year ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).