Which statement best describes the squared root of 50?

Which side lengths cannot form a triangle?

sineoko [7]

Answer:

answer is option A

A, 4+12>6✓

12+6>4✓

4+6>12×

because sum of two sides lengths ina a triangle should greater than the other side's length

5 0

3 years ago

Read 2 more answers

A recent national survey indicated that 73 percent of respondents try to include locally grown foods in their diets. A 95 percen

lilavasa [31]

Answer:

Correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

Step-by-step explanation:

A hypothesis for the proportion of people who include locally grown foods in their diets can be defined as:

H₀: The proportion of people who include locally grown foods in their diets is p.

Hₐ: The proportion of people who include locally grown foods in their diets is difference from p.

The decision rule can be based on the 95% confidence interval.

If the confidence interval consists the hypothetical value of the true proportion then the null hypothesis will be accepted or else the null hypothesis will be rejected.

The 95% confidence interval for the proportion of all people in the country who try to include locally grown foods in their diets is given as (0.70, 0.76).

This interval implies that there is 0.95 probability that the true proportion of people who include locally grown foods in their diets is between 70% and 76%.

Assuming that the claim made was supported by the 95% confidence interval.

The claim should be:

Less than 75% of all people in the country try to include locally grown foods in their diets.

Because the 95% confidence interval defines the range of the true proportion as 70% to 76%. Most of the values are below 75%.

Thus, the correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

3 0

3 years ago

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I NEED HELP ASAP. PLEASE TELL ME WHERE I WOULD GRAPH AND WHERE I WOULD SHADE. ALSO IF THE LINE WOULD BE SOLID OR NOT. 20 POINTS

luda_lava [24]

The first one is a dashed line and the second one is solid. Two points for the first one is (1,4) and (0,3). For the second one two points are (0,-3) and (1,0). From build the lines. Finally the first one is where y is greater so shade above the line with points like ( 10,10) or (7,8) in the shaded region. For the second one since y is less or equal to shade below the line with points like (-2,-10) or (-1,-5).

3 0

3 years ago

Inferential statistics allow you to decide whether a difference between the experimental and the control group is due to:_______

den301095 [7]

Answer:

Option (A)

Step-by-step explanation:

There are 2 main branches of statistics. They are:

1. Descriptive Statistics

2. Inferential Statistics

Descriptive statistics describes the characteristics of observed subjects or items while Inferential statistics makes inferences, based on given or derived data.

Inferential Statistics allow you to decide whether a difference between the experimental group and control group is due to manipulation or chance.

The Experimental group is the group that an effect is tested on while the Control group is the group that is left untested or uninfluenced. Inferential statistics allow you to decide whether a difference between these 2 groups is due to

- manipulation or interference by any force (which may be the experimenter/researcher)

or

- probability which is chance.

5 0

3 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

2 years ago