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Y_Kistochka [10]
3 years ago
15

Which of the following statements are true?

Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

last one

Step-by-step explanation:

they both whole

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Solve the equation x² + 6x + 1 = 0. give your answer to two decimal places
Alexandra [31]

Answer:

x ≈ - 5.83 , x ≈ - 0.17

Step-by-step explanation:

x² + 6x + 1 = 0 ( subtract 1 from both sides )

x² + 6x = - 1

Using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(3)x + 9 = - 1 + 9

(x + 3)² = 8 ( take square root of both sides )

x + 3 = ± \sqrt{8} ( subtract 3 from both sides )

x = - 3 ± \sqrt{8}

Then

x = - 3 - \sqrt{8} ≈ - 5.83 ( to 2 dec. places )

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5 0
3 years ago
Can someone please help me?
ss7ja [257]

For each square root, you can simplify the expression under the root as

3\sqrt{98xy}=3\sqrt{2\cdot7^2xy}=3\cdot7\sqrt{2xy}=21\sqrt{2xy}

\sqrt{108y}=\sqrt{2^2\cdot3^3xy}=2\cdot3\sqrt{3xy}=6\sqrt{3xy}

2\sqrt{75xy}=2\sqrt{3\cdot5^2xy}=2\cdot5\sqrt{3xy}=10\sqrt{3xy}

So we have

3\sqrt{98xy}-\sqrt{108xy}+2\sqrt{75xy}=21\sqrt{2xy}-6\sqrt{3xy}+10\sqrt{3xy}

=21\sqrt{2xy}+4\sqrt{3xy}

This means [1] = 4 and [2] = 3xy.

7 0
3 years ago
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