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2 years ago

Solve for b 3(b-2) =2b+9

2 answers:

6 0

First distribute the 3

3b-6 = 2b+9

Then add 6 to each side of the equation

3b = 2b+15

Next subtract 2b from each side of the equation

b = 15

Your answer is b = 15

I hope this helps!

jarptica [38.1K]2 years ago

5 0

3b - 6 = 2b + 9
3b-2b=9+6
b=15

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Question 7

serg [7]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a cone with volume 769?3 ft³ , having a height of 15 ft

To calculate - radius of the cone

We know that ,

$\bold{Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h }\\$

substituting the values in the formula stated above ,

$\bold{769.3 = \frac{1}{3} \times 3.14 \times r {}^{2} \times 15} \\ \\\bold{\implies r {}^{2} = \frac{769.3 \times 3}{3.14 \times 15} } \\ \\\bold{\implies r {}^{2} = \cancel\frac{2307.9}{47.1}} \\ \\\bold{ \implies \: r {}^{2} = 49} \\ \\ \bold{\implies \: r = 7 \: ft}$

therefore ,

radius = 7 cm

hope helpful ~

4 0

2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

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3 years ago

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Ilia_Sergeevich [38]

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docker41 [41]

Answer: True

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