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adell [148]
3 years ago
10

What is the least possible degree of a polynomial that has roots -5,1 + 4i, and -4i?

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Without any extra conditions, the answer could be 3, and the simplest polynomial with the given roots would be

(<em>x</em> + 5) (<em>x</em> - (1 + 4<em>i</em> )) (<em>x</em> + 4<em>i</em> )

= <em>x</em> ³ + 4<em>x</em> ² + (11 - 4<em>i</em> ) <em>x</em> + 80 - 2<em>i</em>

<em />

If the polynomial is supposed to have only <em>real</em> coefficients, then any complex roots must occur along with their complex conjugates:

(<em>x</em> + 5) (<em>x</em> - (1 + 4<em>i</em> )) (<em>x</em> - (1 - 4<em>i</em> )) (<em>x</em> + 4<em>i</em> ) (<em>x</em> - 4<em>i </em>)

= <em>x</em> ⁵ + 3<em>x</em> ⁴ + 23<em>x</em> ³ + 133<em>x</em> ² + 112<em>x</em> + 1360

and then the degree would be 5.

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Answer:

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Step-by-step explanation:

I think so, probably.

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Given that f(x) = 5x^2-3x+7 and f(g(x))=(5x^4)/9 + (17x^2)/3 + 21. Find all possible values for the sum of the coefficients in t
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steps

(x) = 5x^2-3x+7

refine

x=5x^2-3x+7

Switch sides

5x^2-3x+7-x=x-x

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2(3x – 1) = 6x – 2 number of solutions
Alexxandr [17]

Answer: All real numbers are solutions.

Step-by-step explanation:

Let's solve your equation step-by-step.

2(3x−1)=6x−2

Step 1: Simplify both sides of the equation.

2(3x−1)=6x−2

(2)(3x)+(2)(−1)=6x+−2(Distribute)

6x+−2=6x+−2

6x−2=6x−2

Step 2: Subtract 6x from both sides.

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Step 3: Add 2 to both sides.

−2+2=−2+2

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