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Papessa [141]
2 years ago
8

7. A number of minor automobile accidents occur at various high-risk intersections in Teton County despite traffic lights. The T

raffic Department claims that a modification in the type of light will reduce these accidents. The county commissioners have agreed to a proposed experiment. Eight intersections were chosen at random, and the lights at those intersections were modified. At the .01 significance level, is it reasonable to conclude that the modification reduced the number of traffic accidents?
Mathematics
1 answer:
Anit [1.1K]2 years ago
6 0

Answer:

Modification has not reduced the number of accidents.

Step-by-step explanation:

H_0: \mu\geq0\\H_a:\mu

                                 A  B  C   D   E   F  G   H

Before modification 5  7  6   4    8   9   8   10

After modification    3  7  7   0    4   6   8    2

Difference                -2 0  1   -4   -4   -3  0   -8

Mean of differences M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5

Standard deviation of differences = \sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277

Formula of paired t test :

t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152

Df = n-1 = 8-1 =7

t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998

t critical> t calculated

So, We failed to reject null hypothesis

Hence modification has not reduced the number of accidents.

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Anton [14]

Answer:

The answer is D. x= 4

Step-by-step explanation:

The angles are congruent so

2.3x +25 = 5.8x + 11

2.3x - 5.8x = 11 - 25

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x = 14/3.5

x = 4.

5 0
3 years ago
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Please help me answer these 2 questions with a FULL explanation so I know how to do the rest myself. Giving brainliest.
sveticcg [70]

Answer to 1:

\frac{x^3}{2y^25}

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

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2 years ago
Helpppppp asappppp pls <br><br> Show your work <br> I’ll give brainliest!!!!!!
sineoko [7]

Answer: 3360 ft squared

Step-by-step explanation:

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2 years ago
A five feet tall man casts a shadow rhat is 4 1/3 feet long. A telephone pole casts a shadow that is 25.5 feet long. How tall is
Burka [1]

Answer:

22.1 inches

Step-by-step explanation:

The shadow is formed at a specific factor of the original image hence if a 5 feet tall man casts a shadow rhat is 4 1/3 feet long then a  telephone pole casts a shadow that is 25.5 feet long must have a length

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5 / 13/3 = x/ 25.5

15/13 = x/25.5

cross multiply

15 * x = 13 * 25.5

Divide both sides by 15

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x = 22.1 inches

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vladimir2022 [97]

Answer:

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