Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given

The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.

Slope intercept form is:

Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation

Putting the values of b and m

Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
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