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shepuryov [24]
3 years ago
10

Please help with this question! Thanks in advance...

Physics
1 answer:
-Dominant- [34]3 years ago
5 0

A.0.6 hope you do good on your test!!

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The pattern of _______ in an area over a long period of time is called _______. A. Climate, temperature B. Weather, climate C. W
lianna [129]

The pattern of weather in an area over a long period of time is called 'climate'. <em>(B)</em>

In other words:  

-- What it's like outside your house today, in the middle of March, is the 'weather'.

-- The 100-years average of what it's like outside your house in the middle of March is the 'climate'.  

6 0
4 years ago
Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist
steposvetlana [31]

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge q = -6.25 \times 10^{-6}C

Separation between two charges r = 0.02 m

For finding the electrical force,

According to the coulomb's law

   F = \frac{k q^{2} }{r^{2} }

Here, force between two balloons are repulsive because both charges are same.

Where k = 9 \times 10^{9}

   F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2}  }{4 \times 10^{-4} }

   F = 878.9 N

Therefore, the electric force between them is 878.9 N

8 0
3 years ago
A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant accelerat
UkoKoshka [18]

Answer:

a = -2.82 m/s²

v = 18.4 m/s

Explanation:

Initial velocity, u = 26.0 m/s

Final velocity, v = 0 m/s

Distance travelled, s = 120m

Using

v² = u² + 2as

0 = 26² + 2(120)a

a= -2.82 m/s²

Velocity of the car when it was 60.0m past the point where the brakes were applied:

u = 26.0 m/s

a = -2.82 m/s²

s = 60m

Using

v² = u² + 2as

v² = 26² + 2(-2.82)(60)

v² = 337.6

v = 18.4 m/s

5 0
3 years ago
Why sound are more audible at night then in a day ? (please hope answer will not be too long)​
mojhsa [17]

<em><u>Answer:</u></em>

You can only hear it at night. The reason for this upward diversion of sound in the daytime versus the downward diversion at night is the strong dependency of the speed of sound in the atmosphere on temperature. The atmosphere acts like a lens that focuses sound energy upwards during the day, but keeps it at ground level during the night.

<em><u>Or</u></em>

<em><u>During the day, the sound bends away from the ground; during the night, it bends towards the ground. Hence at night you have additional "sound" reaching you, making it louder.</u></em><em><u> </u></em>

This is the Answer for your question :3

I hope you are having a great day ❤️❤️❤️❤️❤️

5 0
3 years ago
Read 2 more answers
An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p
sladkih [1.3K]

Answer:

3.4 x 10⁴ m/s

Explanation:

Consider the circular motion of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of electron = 9.1 x 10⁻³¹ kg

v  = radial speed

r = radius of circular path = 2 mm = 0.002 m

q = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

For the circular motion of electron

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Consider the linear motion of the electron :

v' = linear speed

x = horizontal distance traveled = 9 mm = 0.009 m

t = time taken = \frac{2\pi m}{qB} = \frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})} = 4.5 x 10⁻⁷ sec

using the equation

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

Speed is given as

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

6 0
4 years ago
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