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Radda [10]
4 years ago
5

What is the relation of the sign of the charge on the charging body to the sign of the charge on the charged body when the charg

ing is by contact
Physics
1 answer:
galben [10]4 years ago
7 0

Charging by conduction involves the contact of a charged object to a neutral object. .

<u>Explanation:</u>

  • Suppose that a charged aluminum plate is touched to a neutral metal sphere, the neutral metal sphere becomes negatively charged because of the results of being contacted by the charged aluminum plate.
  • A charged metal sphere is touched to the highest plate of a neutral needle measuring instrument, the neutral measuring instrument becomes charged because of the results of being contacted by the metal sphere.
  • For example, a student standing on an insulating platform touches a negatively charged Van de Graaff generator, the neutrally charged student becomes charged. This is due to the contact made with the Van De Graaff generator which is negatively charged.

 

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The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of 216 km/h. (a) If the train goes
faust18 [17]

Answer:

a)  r = 6122 m and b) v = 32.5 m / s

Explanation:

a) The train in the curve is subject to centripetal acceleration

         a = v2 / r

Where v is The speed and r the radius of the curve

They indicate that the maximum acceleration of the person is 0.060g,

        a = 0.060 g

        a = 0.060 9.8

        a = 0.588 m /s²

Let's calculate the radius

        v = 216 km / h (1000m / 1km) (1 h / 3600 s =

        v = 60 m / s

        r = v² / a

        r = 60² /0.588

        r = 6122 m

b) Let's calculate the speed, for a radius curve 1.80 km = 1800 m

        v = √a r

        v = √( 0.588 1800)

        v = 32.5 m / s

6 0
3 years ago
How does heat travel between objects that are not touching each each another
skad [1K]
Through heat waves I'm pretty sure
8 0
3 years ago
Read 2 more answers
A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m
Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

Put the value into the formula

W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0
3 years ago
Which planet is smaller than EarthÍs core?
Juliette [100K]
The Earth's core is estimated to be bigger than both Mars and Mercury. However, I would say that Mercury is the safest choice. Mercury is also known to be smaller than Jupiter's Moon!
3 0
3 years ago
Covert 60 mph to SI mks units
Flauer [41]

26.82m/s

Explanation:

Given:

   speed = 60mph

 problem: convert to m/s

To solve this problem, we have to find the right and appropriate conversion factor which equals to 1 to multiply this unit with:

   we are converting:

      miles to meters

      hours to seconds

    1.609km = 1mile

      1000m = 1km

  60s = 1 min

   60 min = 1hr

Now to convert from mph to m/s

  60 x    \frac{mi}{hr}  x  \frac{1.609km}{1mi}   x   \frac{1000m}{1km}  x \frac{1hr}{60min}  x \frac{1m}{60s}

  =  26.82m/s

   

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

7 0
3 years ago
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