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Radda [10]
3 years ago
5

What is the relation of the sign of the charge on the charging body to the sign of the charge on the charged body when the charg

ing is by contact
Physics
1 answer:
galben [10]3 years ago
7 0

Charging by conduction involves the contact of a charged object to a neutral object. .

<u>Explanation:</u>

  • Suppose that a charged aluminum plate is touched to a neutral metal sphere, the neutral metal sphere becomes negatively charged because of the results of being contacted by the charged aluminum plate.
  • A charged metal sphere is touched to the highest plate of a neutral needle measuring instrument, the neutral measuring instrument becomes charged because of the results of being contacted by the metal sphere.
  • For example, a student standing on an insulating platform touches a negatively charged Van de Graaff generator, the neutrally charged student becomes charged. This is due to the contact made with the Van De Graaff generator which is negatively charged.

 

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On a horizontal frictionless floor, a worker of weight 0.900 kN pushes horizontally with a force of 0.200 kN on a box weighing 1
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Answer:

D) The worker will accelerate at 2.17  m/s²  and the box will accelerate at 1.08  m/s² , but in opposite directions.

Explanation:

Newton's third law

Newton's third law or principle of action and reaction states that when two interaction bodies appear equal forces and opposite directions. in each of them.

F₁₂= -F₂₁

F₁₂: Force of the box on the worker

F₂₁: Force of the worker on the box

Newton's second law

∑F = m*a

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Formula to calculate the mass (m)

m =  W/g

Where:

W : Weight (N)

g : acceleration due to gravity  (m/s²)

Data

W₁ =1.8 kN   : box weight

W₂ = 0.900 kN : worker weight

F₂₁ = 0.200 kN

F₁₂ = - 0.200 kN

g = 9.8 m/s²

Newton's second law for the box

∑F = m*a

F₂₁ = m₁*a₁    m₁=W₁/g

0.2 kN = (1.8kN)/(9.8 m/s² ) *a₁

a_{1} =\frac{(0.2kN)*9.8\frac{m}{s^{2} } }{1.8 kN}

a₁= 1.08 m/s² : acceleration of the box

Newton's second law for the worker

∑F = m*a

F₁₂ = m₂*a₂ , m₂=W₂/g

- 0.2 kN =( (0.9 kN) /(9.8 m/s² ) )*a₂

a_{1} =\frac{(0.2kN)*9.8\frac{m}{s^{2} } }{0.9 kN}

a₂=  -2.17 m/s² : acceleration of the worker

5 0
3 years ago
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