How do you derive the drift velocity equation (I = nAve)?

1 answer:

4 0

Current is just number of electrons (times its charge) passing by in a given time (in seconds for amps). say you have a volume filled with moving electrons (ignore the inner shell electrons since they stay put) if this volume is constantly moving, the current is just the total charge of this moving volume divided by the total time it takes to pass a certain surface. total charge is e*n*A*L where l is the length (this is just total volume*charge density*charge/electron) the time it takes this to move a distance L is the time for all the charges to move across some 'measuring' surface, time=distance/velocity=L/v Current=total charge/total time=enAL/[L/v]=nAve this is one way to think about it... I hope I helped! ☺️

You might be interested in

What quickly forms on a cold glass on a hot day.

Zanzabum

Dew - small water drops, happens all the time, even to windows.

8 0

3 years ago

A man pushes on piano with mass 170 kg; it slides at constant velocity down a ramp that is inclined at 20.0 ∘ above the horizont

nikdorinn [45]

Answer

given,

mass of the piano = 170 kg

angle of the inclination = 20°

moves with constant velocity hence acceleration = 0 m/s²

neglecting friction

so, force required to pull the piano

F = m g sin θ

F = 170 × 9.81 × sin 20°

F = 570.39 N

so, force required by the man to push the piano is F = 570.39 N

4 0

3 years ago

Why can gases be compressed

Keith_Richards [23]

Gases can be compressed, because they just take up the space surrounding them. The attractive forces between the particles in a gas are very weak, so the particles are free to move in random direction. They just move along until they collide, either with the walls of the container or with each other. Moreover, gases can be compressed because the particles are far apart and they have space to move into.

5 0

3 years ago

A small mailbag is released from a helicopter that is descending steadily at 3 m/s.

mario62 [17]

<u>Answer:</u>

a) Speed of mailbag after 3 seconds = 32.4 m/s

b) Package is 44.1 meter below helicopter

c) If the helicopter was rising steadily at 3.00 m/s

Speed of mailbag after 3 seconds = 26.4 m/s

Package is 44.1 meter below helicopter

<u>Explanation:</u>

a) We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.