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GalinKa [24]
3 years ago
6

A Styrofoam box has a surface area of 0.73 m and a wall thickness of 2.0 cm. The temperature of the inner surface is 5.0°C, and

the outside temperature is 25°C. If it takes 8.4 h for 5.0 kg of ice to melt in the container, determine the thermal conductivity of the Styrofoam W/m-K
Physics
1 answer:
Elis [28]3 years ago
5 0

Answer:

K = 0.076 W/m K

Explanation:

Heat required to melt the complete ice is given as

Q = mL

here we have

m = 5.0 kg

L = 3.35 \times 10^5 J/kg

now we have

Q = (5 kg)(3.35 \times 10^5)

Q = 1.67 \times 10^6 J

now the power required to melt ice in 8.4 hours is

P = \frac{Q}{t} = \frac{1.67\times 10^6}{8.4 \times 3600 s}

P = 55.4 Watt

now by formula of conduction we know

P = \frac{KA(\Delta T)}{x}

now we have

55.4 = \frac{K(0.73 m^2)(25 - 5)}{0.02}

K = 0.076 W/m K

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