Britney bought 3 gallons of juice for $2.75 per gallon. She sold the juice 1-cup servings for $0.80 each. Each serving is 1/16 g
1 answer:
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Answer:
48 kg
Step-by-step explanation:
The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.
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<h3>setup</h3>Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...
x/y = 8/9
After the changes in weight, they were equal:
x+2 = y-4
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<h3>solution</h3>Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.
y = x +6 . . . . . . . . . . solve the second equation for y
x/(x+6) = 8/9 . . . . . . substitute for y in the first equation
9x = 8(x +6) . . . . . . . multiply by 9(x+6)
x = 48 . . . . . . . . . . . simplify and subtract 8x
Jane weighed 48 kg at first.
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<em>Alternate solution</em>
The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.
(This mental solution is virtually the same as the solution using equations shown above.)
Answer:
53.13
Step-by-step explanation:
To find the measure of an angle use an inverse trig function.
so you can take the inverse to find A
.
Use a calculator to calculate the value.
A = 53.13
Answer:
101.9 sq ft
Step-by-step explanation:
The figure is missing: find it in attachment.
Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.
We have in total 5 faces:
- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is
- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is
- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is
- Finally, we have 2 triangular faces (top and bottom), so their area is
where
b = 5.1 ft is the base
h = 6.8 ft is the height (because the triangle is a right triangle)
So the area of the triangle is
So the total lateral surface area of the figure is:
