1/2 < 3/4
1/2 is = 2/4
and 2/4 < 3/4
therefore 1/2 must be < 3/4
By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>
In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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Answer: The zero will be at 2 when the line hit the x-axis
Step-by-step explanation:
Caculate
Answer:
96m
Step-by-step explanation:
12m * 8 = 96m
unless lengths are counted as to one side and back then it would be double 96
Answer:
C.
Step-by-step explanation:
The relationship is proportion if y/x is constant.
So it is C because 12/4 = 15/5 = 18/6 = 3.