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fiasKO [112]
2 years ago
6

A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. Fo

r the half life: The half life is the solution (t) of the equation : a2=ae−7.571t a 2 = a e − 7.571 t
Mathematics
1 answer:
vovikov84 [41]2 years ago
6 0
The decay function is
a(t)=a_{0} e^{-7.571t}
where
a₀ = initial mass
t = time, days

At half life, a(t) = a₀/2, therefore the time required to achieve half life is given by the equation
\frac{a_{0}}{2} =a_{0} e^{-7.751t}\\ \frac{1}{2} =e^{-7.571t}

Take natural log of each side.
ln(1/2) = -7.571 t

Divide each side by -7.571 to obtain
t= \frac{ln(1/2)}{-7.571} =0.0916

Answer: 0.0192 days (nearest thousandth)
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In what time the compound amount of Rs 60000 at 10% rate is rs 79860?​
Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

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R= ?  

Applying the formula A= P (1+r/100)^T

           79860  = 60000 (1+ r/100)^3

                  79860/60000 = (1+r/100)^3

                  1331/1000 = (1+r/100)^3

root(3)(1331/1000) = (1+r/100)

                     11/10 = 1+r/100

                     11/10 -1 = r/100

                      1/10 = r/100

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Step-by-step explanation:

8 0
3 years ago
Find the complex zeros of x^3+27. write f in factored form
aliina [53]
x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0


4 0
3 years ago
(-4^-2) (49^-1/2)<br><br> Evaluate the expression
Marizza181 [45]

Answer:

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Step-by-step explanation:

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5 0
1 year ago
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Galina-37 [17]
1.)combine like terms: 12-2x=10x 3-10=-7

10x-7
4 0
2 years ago
Read 2 more answers
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adoni [48]
I'll write the equation again with the blanks filled in.

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Hope this helps!
6 0
2 years ago
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