The length of a pool is 3 feet more than twice its width. If the perimeter of the pool is 72 feet, find the dimensions of the po
ol by writing and solving a system of equations.
2 answers:
![[tex]x-length\\ y-width\\ x=2y+3\\ Perimeter: 2x+2y=72\\\\ System\ of\ equations:\\ \left \{ {{x=2y+3} \atop {2x+2y}} \right. \\ Substituting\ x=2y+3\\ 2(2y+3)+2y=72\\ 4y+6+2y=72\\ 66y=60|:6\\ y=11\\x=2y+3=2*11+3=25](https://tex.z-dn.net/?f=%5Btex%5Dx-length%5C%5C%20y-width%5C%5C%20x%3D2y%2B3%5C%5C%20Perimeter%3A%202x%2B2y%3D72%5C%5C%5C%5C%20System%5C%20of%5C%20equations%3A%5C%5C%20%5Cleft%20%5C%7B%20%7B%7Bx%3D2y%2B3%7D%20%5Catop%20%7B2x%2B2y%7D%7D%20%5Cright.%20%5C%5C%20Substituting%5C%20x%3D2y%2B3%5C%5C%202%282y%2B3%29%2B2y%3D72%5C%5C%204y%2B6%2B2y%3D72%5C%5C%2066y%3D60%7C%3A6%5C%5C%20y%3D11%5C%5Cx%3D2y%2B3%3D2%2A11%2B3%3D25)
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