Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating
rectangle.
x = 28 − 7y2,
x = 7y2 − 28
x = 28 − 7y2,
x = 7y2 − 28
1 answer:
Answer:
V=25088π vu
Step-by-step explanation:
Because the curves are a function of "y" it is decided to take the axis of rotation as y
, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2
f(y)₁ = 7y²-28; f(y)₂=28-7y²
y=0; x=28-0 ⇒ x=28
x=0; 0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2
Knowing that the volume of a solid of revolution V=πR²h, where R²=(r₁-r₂) and h=dy then:
dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy
dV=4π(49y⁴-392y²+784)dy integrating on both sides
∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving ∫(49y⁴-392y²+784)dy
49∫y⁴dy-392∫y²dy+784∫dy =
V=4π( ) evaluated -2≤y≤2, or 2(0≤y≤2), also
⇒ V=25088π vu
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Answer:
a) P(X = 0) = 0.5997
b) P(X = 9) = 0.0016
c) P(X = 8) = 0.0047
d) P(X = 5) = 0.4018
Step-by-step explanation:
These following problem are examples of the binomial probability distribution.
Binomial probability
Th binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And is the probability of X happening.
(a) for n = 4 and π = 0.12, what is P(X = 0)?
(b) for n = 10 and π = 0.40, what is P(X = 9)?
(c) for n = 10 and π = 0.50, what is P(X = 8)?
(d) for n = 6 and π = 0.83, what is P(X = 5)?