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anyanavicka [17]
3 years ago
5

Given: A6, 4), M(8, 1) Find: B

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

Coordinates for B= (10,-2)

Step-by-step explanation:

The solution is shown in the image provided step by step, as it was not possible typing it on this given space here. Hope it helps :)

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Problem: A scuba diver swam 30 feet below sea level. After a couple of minutes, he went down 10 feet more. Find the total distan
QveST [7]

Answer: -40 feet

Step-by-step explanation: the scuba diver starts at sea level (0) then swims down 30 feet (-30). after a couple minutes, goes down 10 feet more (-40) the scuba diver will now be -40 down from sea level. so it should be -40 because the scuba diver swam that much down.

lmk if this is incorrect, i'm not quit sure if it is or not. if i'm wrong, i'm so sorry!!

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3 0
3 years ago
The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
3 years ago
34560×23458÷34 <br><br>yo what's the answer
Phoenix [80]

Answer:

23,163,099.42857

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7 0
3 years ago
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PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!
8_murik_8 [283]

Step-by-step explanation:

let m2 be x

then m1 = 4x

Since, m1+m2 = 115

therefore x + 4x = 115

5x = 115

x = 23

so , m2 = 23°

3 0
2 years ago
Read 2 more answers
Find the slope for each of the order pair. (-2,-1) and (8,-3)
kondaur [170]

Answer:

-0.2

Step-by-step explanation:

Slope (m) =ΔY/ΔX= 8-(-2)/-3-(-1)

= -1/5

= -0.2

4 0
3 years ago
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