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stealth61 [152]
3 years ago
10

What is the answer to 7w² + 25-2w

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0

Answer

7w²-2w+25

Step-by-step explanation:

That is written in standard form according to their degrees.

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The answer is 13.7 and rounded to the nearest hundredth is 14
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Choose the estimate closest to an average​ person's weight: 8​kg, 80​kg, or 800 kg.
dexar [7]

The estimate closest to an average​ person's weight is 80​kg

<h3>How to determine the estimate?</h3>

The weights are given as:

8 kg, 80 kg and 800 kg

To answer this question, I will assume that a person means an adult

An adult that weighs 8 kg is very much under weight

Because the average weight of a person is around 60 to 90 kg

Hence, the estimate closest to an average​ person's weight is 80​kg

Read more about weights at:

brainly.com/question/2337612

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2 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
The distance around a meteor crater is 9,471 ft. Find the diameter of the crater. Use
matrenka [14]

Answer:

The distance around the crater is 9415.  If the crater is in the shape of a circle then this distance is the circumference of the circle.  The circumference C and diameter D of a circle are related by the formula

C = PI * D

If you plug in 9415 for C and 22/7 for PI and solve for D you get

9415 = (22/7) * D

D = (7/22) * 9415 ~ 2995.7

Step-by-step explanation:

U must like COD

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Do you still have time Bc if so use this 2 times pie times 5
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