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3 years ago

7

Britta brought some carrots and apples for $24.80. A carrot and apple cost $0.90 altogether. She brought more carrots than apple

s. The cost of extra number of carrots was $6.80. How many apples did Britta buy?

1 answer:

irga5000 [103]3 years ago

7 0

The extra cost of the apples and the carrots is 5 dollors and 90 cent

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

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Which expression is equivalent to 12(2+3x−6) ?

matrenka [14]

Simplify: 12(2 + 3x - 6)
= (12)(2 + 3x + - 6) = (12)(2) + (12)(3x) + (12)( - 6)
= 24 + 36x - 72
Answer = 36x - 48

2: Factor:

36x - 48
= 12(3x -4)

Answer
= 12(3x -4)

3: <span>12(2+3x−6)

= 12(3x + 2 - 6)

= 12(3x - 4)

Your Answer would be (A).

3x - 4</span>

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A young sumo wrestler decided to go on a diet to gain weight rapidly. He gained weight at a rate of 5.5kg a month. After 11 mont

kondaur [170]

Answer:

$W(t)=5.5t+79.5$ .

Step-by-step explanation:

Please consider the complete question.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).

Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.

Now, we will use point-slope form of equation as:

$y-y_1=m(x-x_1)$ , where,

m = Slope

$(x_1,y_1)$ = Given point on the line.

Upon substituting coordinates of point (11,140) in above formula, we will get:

$y-140=5.5(x-11)$

$y-140=5.5x-60.5$

$y-140+140=5.5x-60.5+140$

$y=5.5x+79.5$

Therefore, our required function would be $W(t)=5.5t+79.5$ .

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Which statement is true?

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The statement that would be considered be as true is "<span>In a regular hexagon, the length of the radius is the same as the length of a side. In addition, a hexagon could be sliced forming triangles that are equilateral therefore having the same length of sides and similar interior angles. </span>

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((-196z^3)/(y^21))-(2z/y^7)

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