SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees
Answer:
Yes, 2 and 0 are the zeroes.
Step-by-step explanation:
Given polynomial: x²-2x
p(2)= 2²-2(2)
= 4-4
= 0
p(0)= 0² -2(0)
= 0-0
= 0
This is the concept of volumes of solid figures;
To calculate for the volume of material required we calculate for the volume of the pyramid;
volume of the pyramid is given by:
volume=(length*width*height)/3
but in our case the base of the pyramid is square, therefore:
length=width=2 ft
height=6 ft
hence;
volume=(2*2*6)/3
volume=8 ft^3
The answer is 8 ft^3
A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C
so.. C is the difference of all the three angles from 360 or
![\bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148](https://tex.z-dn.net/?f=%5Cbf%20%5Cmeasuredangle%20C%3D360-x-%282x%2B1%29-148%5Cimplies%20%5Cmeasuredangle%20C%3D360-x-2x-1-148)
whatever that is, now, you'll get some value in x-terms
so.... now once we know what C is
you can if you want, do a search in google for "inscribed quadrilateral conjecture", I can do a quick proof if you need one
but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°
so.. what the dickens does all that mean? well D+B=180 and A+C = 180
now. we know what A is, 2x+1
and by now, you'd know what C is from 360-x-2x-1-148
so... add them together then and
![\bf \begin{array}{cccclllll} A&+&C&=&180\\ \uparrow &&\uparrow \\ (2x+1)&+&(360-x-2x-1-148)&=&180 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bcccclllll%7D%0AA%26%2B%26C%26%3D%26180%5C%5C%0A%5Cuparrow%20%26%26%5Cuparrow%20%5C%5C%0A%282x%2B1%29%26%2B%26%28360-x-2x-1-148%29%26%3D%26180%0A%5Cend%7Barray%7D)
solve for "x"