Given:
To find:
The quadrant in which 
lie.
Solution:
Quadrant concept:
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II, only 
and 
are positive.
In Quadrant III, only 
and 
are positive.
In Quadrant IV, only 
and 
are positive.
We have,
Here, is negative and is also negative. It is possible, if 
lies in the Quadrant IV.
Therefore, the correct option is D.
Ok, so what we want to do here is first remove the repeating decimal.
x=2.16 repeating
10x=21.6 repeating
100x=216.6 repeating
Subtract 10x=21.6 repeating from 100x=216.6 repeating. This will get rid of the repeating numbers.
100x=216.6 repeating
-10x=21.6 repeating
__________________
90x=195
Divide both sides by 90.
x=195/90
Now you can simplify that into 13/6.
1.
75 km/h
75*20= 1500
Traveled 1500 kilometers
2.
1 mile = 1.60934 km
75/1.60934=
<span>46.6029552487
</span>or 46.6 mph, or below the speed limit
a. my opposite sides are parallel
FALSE. Only the basis sides are parallel.
<u>b. I am a quadrilateral </u>
TRUE. A trapezium has 4 sides.
c. I have all the sides equal
FALSE. The trapezium is a special shape in that it does not, unlike the square or rectangle, have to have any equal side lengths.
