I understand this but I want to be sure I’m right help me pls

Mathematics

1 answer:

Bad White [126]2 years ago

5 0

Answer:

Step-by-step explanation:

∡WXY = 138° - ∡ZXY

You might be interested in

how man 1/3 inch cubes does it take to fill a box with width 2 2/3 inches,lenght 3 1/3 inches and height 2 1/3

galben [10]

idk anymore ;-; please WELP ME

3 0

3 years ago

The following steps are used to rewrite the polynomial expression, 3(x + 4y) + 5(2x - y).

ololo11 [35]

Answer:

step1 - distributive property

step2 - associative property

step3 - cumulative property

step4 - associative property

Step-by-step explanation:

3 0

2 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$