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just olya [345]
3 years ago
6

Parallelogram RECT is a rectangle. If EC = x + y , RT = 2x - y, RE = 2x + y, and TC = 3x - 3 , what are the values of the variab

le
Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
<h2>The values of the variable are 3 and 6.</h2>

Step-by-step explanation:

In parallelogram RECT is a rectangle,

EC = x + y , RT = 2x - y, RE = 2x + y and TC = 3x - 3

To find, the values of the variable = ?

∵ The opposite sides are equal.

∴ RE = TC and RT = EC

2x + y = 3x - 3

⇒ x - y = 3                   .......... (1)

Also,

2x - y = x + y

⇒ x - 2y = 0               .......... (2)      

Subtracting (1) from (2), we get

∴ x - y - (x - 2y ) = 3 - 0

⇒ x - y - x + 2y = 3

⇒ y = 3

Put y = 3 in equation (1), we get

x - 3 = 3  

⇒ x = 3 + 3 = 6

∴ x = 6 and y = 3

Thus, the values of the variable are 3 and 6.

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What is the slope of (3, 3) and (-6, -3)
Veronika [31]

Answer:

m=2/3

Step by Step Explanation:

x1,y1= 3,-6

x2,y2=3,-3

m={-3-3}           (Fraction Form)

    {-6-3}

Refine:

m={2}{3}

7 0
2 years ago
Read 2 more answers
Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz
Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The <em>vertical</em> component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>horizontal</em> direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>vertical</em> direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

Read more:

brainly.com/question/24629099

4 0
2 years ago
Read 2 more answers
The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual
hoa [83]

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = 8 \times 35 = 280 \ water\ bottles

14 packs of candy = 14 \times 20 = 280 \ candies

Since the quantities of water bottles and candies are same this is an opt answer.

6 0
3 years ago
Read 2 more answers
Justin solved this problem.
aleksklad [387]
The answer is A, yes his answer is reasonable because 6 times 0.74 is 44.4
4 0
2 years ago
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what is the equation of the following line? Be sure to scroll down first to see all answer options. ( -1/2, -3) ( 0, 0)
dlinn [17]
I got y = 1/5x fo this one.............
5 0
3 years ago
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