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just olya [345]
3 years ago
6

Parallelogram RECT is a rectangle. If EC = x + y , RT = 2x - y, RE = 2x + y, and TC = 3x - 3 , what are the values of the variab

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Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
<h2>The values of the variable are 3 and 6.</h2>

Step-by-step explanation:

In parallelogram RECT is a rectangle,

EC = x + y , RT = 2x - y, RE = 2x + y and TC = 3x - 3

To find, the values of the variable = ?

∵ The opposite sides are equal.

∴ RE = TC and RT = EC

2x + y = 3x - 3

⇒ x - y = 3                   .......... (1)

Also,

2x - y = x + y

⇒ x - 2y = 0               .......... (2)      

Subtracting (1) from (2), we get

∴ x - y - (x - 2y ) = 3 - 0

⇒ x - y - x + 2y = 3

⇒ y = 3

Put y = 3 in equation (1), we get

x - 3 = 3  

⇒ x = 3 + 3 = 6

∴ x = 6 and y = 3

Thus, the values of the variable are 3 and 6.

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Given the equation 6 sin2(x) = 3, we are to find the value of x that satisfies the equation in the interval  [0, 2π]

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Answer:

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Step-by-step explanation:

According to the statement, let A(x,y) = (14,21) and B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A}). The equation of the line in point-slope form is defined by the following formula:

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y - Dependent variable, dimensionless.

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