Please help me ........

Which of the following is equal to 7 1/4?<br> Show work.<br> Please help.

fomenos

d because you take the denominator of the fraction and you put it infront of the square root then you take the numerator and multiply it by the number at hand in this case 7

6 0

4 years ago

Read 2 more answers

The Cinema Center consists of four theaters: Cinemas I, II, III, and IV. The admission price for one feature at the Center is $5

zzz [600]

Answer:

a) Matrix B = $\left[\begin{array}{c}5\\7\\9\end{array}\right]$

b) Matrix AB = $\left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]$

c) $12,695

Step-by-step explanation:

Matrix A = $\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right]$

a) Matrix B = $\left[\begin{array}{c}5\\7\\9\end{array}\right]$

Gross Receipt = AB

$\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right]$ . $\left[\begin{array}{c}5\\7\\9\end{array}\right]$ = $\left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]$

c) Total revenue is the sum of receipts from 4 cinemas given in part b

Hence,

Total revenue = $2525 + $3620 + $2845 + $3705 = $12,695

3 0

3 years ago

Pavel, Ruth and Josh have part-time jobs.

MrMuchimi

M+m+z/3=3m
m+m+z=9m
2m+z=9m
z=7m
m+m+7m/3=3m
9m=9m
m=1
1+1+z/3=3
2+z=9
z=7
idk but i think that one person gets paid 7 dollars and the other ppl get paid 1 dollar----- this is probably veryyyyy wrong

8 0

3 years ago

PLZZZZ HELP!!!!!<br> I WILL GIVE BRAINLIEST AND 5 STAR AND 20 POINTS!!!<br> C=5/9 - (F−32)

ICE Princess25 [194]

Answer:

32 °F

Sorry if I'm wrong

Step-by-step explanation:

3 0

3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

3 0

3 years ago